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If α and β are the roots of the equation x2 - 7x + 1 = 0, then what is the value of
α4
+
β4
?
  • a)
    2207
  • b)
    2247
  • c)
    2317
  • d)
    2337
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If α and β are the roots of the equation x2 - 7x + 1 = 0, then what is...
Concept:
1.
For the quadratic equation ax
2
+ bx + c = 0
Sum of root (α + β) = -b/a
Product of root = c/a
2.
a2 + b
2
= (a + b)
2
- 2ab
3.
a4
+
b4
= (a2 + b2)
2
- 2(
ab)2
Calculation:
x
2
- 7x + 1 = 0
As α & β be roots of the quadratic equation
α + β =
-(-7)/1
α + β
= 7
αβ = 1
By using the above identity
α2 + β2 = (α + β)2 - 2αβ = 72 - 2
α
2
+ β
2
= 47
Now we can use the identity:
α4 + β=
2
+ β
2
)
2
- 2α
2
β
2
Substituting in the value of α2 + β2 and αβ = 1, we get:
α44 + β4 = (47)2 - 2 = 2207
∴ The value of α
4
+ β
4
 is 2207.
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Most Upvoted Answer
If α and β are the roots of the equation x2 - 7x + 1 = 0, then what is...
Given Equation:
The equation given is x^2 - 7x + 1 = 0. Let α and β be the roots of this equation.
Sum and Product of Roots:
From the equation x^2 - 7x + 1 = 0, we know that the sum of the roots (α + β) = 7 and the product of the roots (αβ) = 1.
Using Vieta's Formulas:
We can express α^4 + β^4 in terms of α + β and αβ using the following formula:
α^4 + β^4 = (α^2 + β^2)^2 - 2α^2β^2
We know that (α + β)^2 = α^2 + β^2 + 2αβ
Therefore, α^2 + β^2 = (α + β)^2 - 2αβ
Substitute the values, we get:
α^2 + β^2 = 7^2 - 2(1) = 49 - 2 = 47
Calculating α^4 + β^4:
Now, we can find α^4 + β^4 using the formula:
α^4 + β^4 = (α^2 + β^2)^2 - 2α^2β^2
α^4 + β^4 = 47^2 - 2(1)^2
α^4 + β^4 = 2209 - 2 = 2207
Conclusion:
Therefore, the value of α^4 + β^4 is 2207, which corresponds to option 'A'.
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Question Description
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